When should an array name be treated as a pointer and when does it just represent the array itself? [duplicate]

Posted by user1087373 on Stack Overflow See other posts from Stack Overflow or by user1087373
Published on 2014-06-05T09:07:31Z Indexed on 2014/06/05 9:25 UTC
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arrays

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pointers

This question already has an answer here:

When is an array name or a function name 'converted' into a pointer ? (in C) 4 answers

I just made a test program after reading the book and the result turned out confusing:

    #include <stdio.h>
    int main(void)
    {
        char text[] = "hello!";

        printf("sizeof(text):%d  sizeof(text+2):%d  sizeof(text[0]):%d \n",(int)sizeof(text), sizeof(text+2), sizeof(text[0]));
        printf("text:%p sizeof(text):%d      &text:%p sizeof(&text):%d \n",text, sizeof(text), &text, sizeof(&text));
        printf("text+1:%p  &text+1:%p  \n", text+1, &text+1);

        return 0;
    }

The result:

sizeof(text):7  sizeof(text+2):4  sizeof(text[0]):1 
text:0xbfc8769d sizeof(text):7      &text:0xbfc8769d sizeof(&text):4 
text+1:0xbfc8769e  &text+1:0xbfc876a4

What makes me feel confused are:

why the value of 'sizeof(text)' is 7 whereas 'sizeof(text+2)' is 4
what's the difference between 'text' and '&text'?

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When should an array name be treated as a pointer and when does it just represent the array itself? [duplicate] - Developer IT

When should an array name be treated as a pointer and when does it just represent the array itself? [duplicate]

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